Вывод: код модели, скорость процессора, объем памяти.
with CTE AS
(select
1 n, cast (0 as varchar(16)) bit_or,
code, speed, ram FROM PC
UNION ALL
select n*2,
cast (convert(bit,(speed|ram)&n) as varchar(1))+cast(bit_or as varchar(15))
, code, speed, ram
from CTE where n < 65536
)
select code, speed, ram from CTE
where n = 65536
and CHARINDEX('1111', bit_or )> 0
Отобрать из таблицы Laptop те строки, для которых выполняется следующее условие: значения из столбцов speed, ram, price, screen возможно расположить таким образом, что каждое последующее значение будет превосходить предыдущее в 2 раза или более. Замечание: все известные характеристики ноутбуков больше нуля. Вывод: code, speed, ram, price, screen.
select code, speed, ram, price, screen
from laptop where exists (
select 1 x
from (
select v, rank()over(order by v) rn
from ( select cast(speed as float) sp, cast(ram as float) rm,
cast(price as float) pr, cast(screen as float) sc
)l unpivot(v for c in (sp, rm, pr, sc))u
)l pivot(max(v) for rn in ([1],[2],[3],[4]))p
where [1]*2 <= [2] and [2]*2 <= [3] and [3]*2 <= [4]
)
Вывести название баллончика
with r as (select v.v_name,
v.v_id,
count(case when v_color = 'R' then 1 end) over(partition by v_id) cnt_r,
count(case when v_color = 'B' then 1 end) over(partition by b_q_id) cnt_b
from utV v join utB b on v.v_id = b.b_v_id)
select v_name
from r
where cnt_r > 1
and cnt_b > 0
group by v_name
На основании информации из таблицы Pass_in_Trip, для каждой авиакомпании определить: 1) количество выполненных перелетов; 2) число использованных типов самолетов; 3) количество перевезенных различных пассажиров; 4) общее число перевезенных компанией пассажиров. Вывод: Название компании, 1), 2), 3), 4).
SELECT name,
COUNT(DISTINCT CONVERT(CHAR(24),date)+CONVERT(CHAR(4),Trip.trip_no)),
COUNT(DISTINCT plane),
COUNT(DISTINCT ID_psg),
COUNT(*)
FROM Company,Pass_in_trip,Trip
WHERE Company.ID_comp=Trip.ID_comp and Trip.trip_no=Pass_in_trip.trip_no
GROUP BY Company.ID_comp,name
Вывод: дата, количество рейсов
SELECT DATEADD(day, S.Num, D.date) AS Dt,
(SELECT COUNT(DISTINCT P.trip_no)
FROM Pass_in_trip P
JOIN Trip T
ON P.trip_no = T.trip_no
AND T.town_from = 'Rostov'
AND P.date = DATEADD(day, S.Num, D.date)) AS Qty
FROM (SELECT (3 * ( x - 1 ) + y - 1) AS Num
FROM (SELECT 1 AS x UNION ALL SELECT 2 UNION ALL SELECT 3) AS N1
CROSS JOIN (SELECT 1 AS y UNION ALL SELECT 2 UNION ALL SELECT 3) AS N2
WHERE (3 * ( x - 1 ) + y ) < 8) AS S,
(SELECT MIN(A.date) AS date
FROM (SELECT P.date,
COUNT(DISTINCT P.trip_no) AS Qty,
MAX(COUNT(DISTINCT P.trip_no)) OVER() AS M_Qty
FROM Pass_in_trip AS P
JOIN Trip AS T
ON P.trip_no = T.trip_no
AND T.town_from = 'Rostov'
GROUP BY P.date) AS A
WHERE A.Qty = A.M_Qty) AS D
Вывод: название компании, время в минутах.
select c.name, sum(vr.vr)
from
(select distinct t.id_comp, pt.trip_no, pt.date,t.time_out,t.time_in,--pt.id_psg,
case
when DATEDIFF(mi, t.time_out,t.time_in)> 0 then DATEDIFF(mi, t.time_out,t.time_in)
when DATEDIFF(mi, t.time_out,t.time_in)<=0 then DATEDIFF(mi, t.time_out,t.time_in+1)
end vr
from pass_in_trip pt left join trip t on pt.trip_no=t.trip_no
) vr left join company c on vr.id_comp=c.id_comp
group by c.name
SELECT Q_NAME
FROM utQ
WHERE Q_ID IN (SELECT DISTINCT B.B_Q_ID
FROM (SELECT B_Q_ID
FROM utB
GROUP BY B_Q_ID
HAVING SUM(B_VOL) = 765) AS B
WHERE B.B_Q_ID NOT IN (SELECT B_Q_ID
FROM utB
WHERE B_V_ID IN (SELECT B_V_ID
FROM utB
GROUP BY B_V_ID
HAVING SUM(B_VOL) < 255)))
Используя таблицу Product, определить количество производителей, выпускающих по одной модели.
select count(maker)
from product
where maker in
(
Select maker from product
group by maker
having count(model) = 1
)
Вывести все строки из таблицы Product, кроме трех строк с наименьшими номерами моделей и трех строк с наибольшими номерами моделей.
Select maker, model, type from
(
Select
row_number() over (order by model) p1,
row_number() over (order by model DESC) p2,
) t1
where p1 > 3 and p2 > 3
Вывод: maker, число моделей
select Maker , count(distinct model) Qty from Product
group by maker
having count(distinct model) > = ALL
(select count(distinct model) from Product
group by maker)
or
count(distinct model) <= ALL
(select count(distinct model) from Product
group by maker)
